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自动化测试工程师
分类：seleniumpython验证码
很多网站都有拼图验证码
1。首先要了解拼图验证码的生成原理
2。制定破解计划，考虑其可能性和成功率。
3。编写脚本
拼图验证码实际上是多个小碎片经过重新组合成的一张整体，首先要在网站上抓取这种小碎片图片并下载到本地
先导入必要的包：
import colorsys
import urllib,os,uuid,re,time
from PIL import Image
from mon.action_chains import ActionChains
from selenium import webdriver
抓到并下载到本地
def create(locapath,fileName):
filePath=locapath+'/'+fileName
if not os.path.exists(filePath):
file=open(filePath,'a+')
file.close()
return filePath
def downloadImg():
list = openBrowser()
for i in range(2):
fileName = str(i) + '_test.jpg'
urllib.urlretrieve(list[i], create('/Users/zijiawang/Downloads/', fileName))
time.sleep(3)
def openBrowser():
global wzj
webdriver.Firefox()
wzj.get('https://。。。。')
image1_url = wzj.find_elements_by_class_name('gt_cut_bg_slice')[0].get_attribute('style')
image1_url=image1_url[23:-38]
image2_url = wzj.find_elements_by_class_name('gt_cut_fullbg_slice')[0].get_attribute('style')
image2_url=image2_url[23:-38]
return [image1_url,image2_url]
分割并获取rgb颜色
ef getcolor(image):
list = [[x,y] for x in range(26) for y in range(2)]
listt = []
colors = []
for i in range(len(list)):
l = list[i][0]*12+12
w = list[i][1]*58+58
listt.append([12*0.25+i/2*12, 58*0.25+((i+10)%2)*58])
listt.append([12*0.25+i/2*12, 58*0.75+((i+10)%2)*58])
listt.append([12*0.75+i/2*12, 58*0.25+((i+10)%2)*58])
listt.append([12*0.75+i/2*12, 58*0.75+((i+10)%2)*58])
for i in range(len(listt)):
colors.append(image[listt[i][0],listt[i][1]])
return colors
找出不同的小碎片序号
def getDeferent():
deferent = []
for i in range(208):
if abs(color1[i][2] - color2[i][2]) &20:
print u'B差值: ',color1[i][2]-color2[i][2]
deferent.append(i)
return deferent
def getUPDOWN():
deferent = getDeferent()
xlist = []
ylist = []
for i in deferent:
if (i / 4) % 2 == 0:
xlist.append(i)
ylist.append(i)
uplist = []
downlist = []
for i in xlist:
uplist.append(i / 4)
for i in ylist:
downlist.append(i / 4)
for i in range(len(uplist)):
uplist[i] /= 2
for i in range(len(downlist)):
downlist[i] /= 2
func = lambda x, y: x if y in x else x + [y]
up = reduce(func, [[], ] + uplist)
func = lambda x, y: x if y in x else x + [y]
down = reduce(func, [[], ] + downlist)
return up,down
编写好排列方法，会用的
def bubble(l):
for index in range(len(l) - 1, 0 , -1):
for two_index in range(index):
if l[two_index] & l[two_index + 1]:
l[two_index], l[two_index + 1] = l[two_index + 1], l[two_index]
最后的进行解析，拼装源码。
def end():
orders = getUPDOWN()
orderx = orders[0]
ordery = orders[1]
print 'x:',orderx
print 'y:',ordery
orderX = [145, 157, 277, 265, 169, 181, 253, 241, 97, 109, 301, 289, 73, 85, 37, 25, 1, 13, 133, 121, 49, 61, 229,
217, 193, 205]
orderY = [157, 145, 265, 277, 181, 169, 241, 253, 109, 97, 289, 301, 85, 73, 25, 37, 13, 1, 121, 133, 61, 49, 217,
229, 205, 193]
print u'X:',orderX
print u'Y:',orderY
for x in range(26):
orderX[x] -= 1
orderX[x] /= 12
for y in range(26):
orderY[y] -= 1
orderY[y] /= 12
for i in range(len(orderX)):
for j in range(len(orderx)):
if orderx[j] == orderX[i]:
endX.append(i)
for i in range(len(orderY)):
for j in range(len(ordery)):
if ordery[j] == orderY[i]:
endY.append(i)
print 'endx:',endX
print 'endy:',endY
os.remove('/Users/zijiawang/Downloads/0_test.jpg')
os.remove('/Users/zijiawang/Downloads/1_test.jpg')
all = endX+endY
func = lambda x, y: x if y in x else x + [y]
all_old = reduce(func, [[], ] + all)
all_end =bubble(all_old)
print 'all_end:',all_end
duandata = 1000
for i in range(1,len(all_end)):
if all_end[i]-1 in all_end:
duandata = all_end[i]
print u'断点为:',duandata
if duandata != 1000:
if endX != [] and endY!=[]:
print u'断点1'
guess = [duandata,all_end[0]]
elif endX ==[]:
print u'断点2'
guess = [duandata, endY[0]]
elif endY == []:
print u'断点3'
guess = [duandata,
print u'无断点'
guess = [ all_end[0]]
end_guess =[]
print u'猜测的点:',guess
for i in guess:
end_guess.append(i * 12 - 38)
end_guess.append(i * 12 - 28)
end_guess.append(i * 12 - 20)
end_guess.append(i * 12 - 17)
end_guess.append(i * 12 - 15)
u'猜测的位移量: ',end_guess
return end_guess
if __name__ == '__main__':
downloadImg()
color1 = getcolor(Image.open('/Users/zijiawang/Downloads/0_test.jpg').load())
color2 = getcolor(Image.open('/Users/zijiawang/Downloads/1_test.jpg').load())
guess = end()
for i in guess:
print i,wzj.title
ele = wzj.find_element_by_xpath(
ele = wzj.find_element_by_xpath(
ActionChains(wzj).click_and_hold(ele).perform()
ActionChains(wzj).move_to_element_with_offset(ele, 0,i).perform()
因每个网站的都大同小异，这里不写具体测试的网站了，以免对其造成压力。此算法属于高度定制的，应用其他网站需要改些参数，但是代码注释较小。需要注释，不明白的地方请留言哈。
排名：千里之外
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